파이썬을 무식하게 c처럼 짜보기 10진수를 16진수로 변환

파이썬을 무식하게 c처럼 짜보기 10진수를 16진수로 변환

# -*- coding: utf-8 -*-
m = int(input("정수 입력 : "))
q = 0 # 몫
r = 0 # 나머지
hexNumber = "" # 16진수
while(True):
    if m < 16:
        if m >=0 and m <= 9:
            #print ("{nNumber}".format(nNumber = m))
            hexNumber += str(m)
            break
        else: # m >= 10 and m < 16
            if m == 10:
                #print ("a")
                hexNumber += 'a'
            elif m == 11:
                #print ("b")
                hexNumber += 'b'
            elif m == 12:
                #print ("c")
                hexNumber += 'c'
            elif m == 13:
                #print ("d")
                hexNumber += 'd'
            elif m == 14:
                #print ("e")
                hexNumber += 'e'
            else: # m == 15
                #print ("f")
                hexNumber += 'f'
            break
    elif m == 16:
        hexNumber += str(m%16)
        hexNumber += str(int(m/16))
    else: # m > 16
        #print ("test1")
        r = m%16
        q = int(m/16)
        if r >=0 and r <= 9:
            hexNumber += str(r)
        else: # r >= 10 and r <= 15
            if r == 10:
                # print ("a")
                hexNumber += 'a'
            elif r == 11:
                # print ("b")
                hexNumber += 'b'
            elif r == 12:
                # print ("c")
                hexNumber += 'c'
            elif r == 13:
                # print ("d")
                hexNumber += 'd'
            elif r == 14:
                # print ("e")
                hexNumber += 'e'
            else:  # m == 15
                # print ("f")
                hexNumber += 'f'

        m = q
result = ''.join(reversed(hexNumber))
print (result)